(x/(x^2)-1)-((x+3)/(x^2)+x)=(-3/((x^2)+x)

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Solution for (x/(x^2)-1)-((x+3)/(x^2)+x)=(-3/((x^2)+x) equation: 



(x/(x^2)-1)-((x+3)/(x^2)+x)=(-3/((x^2)+x)

We move all terms to the left:

(x/(x^2)-1)-((x+3)/(x^2)+x)-((-3/((x^2)+x))=0



Domain of the equation: x^2-1)!=0

x∈R





Domain of the equation: x^2+x)!=0

x∈R





Domain of the equation: (x^2+x))!=0

x∈R



We get rid of parentheses

x/x^2-((x+3)/x^2+x)-((-3/(x^2+x))-1=0

We calculate fractions

We do not support expression: x^4

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